Question 243356
2/x+5/(x+2)=1
[2(x+2)+5x]/x(x+2)=1
[2x+4+5x]/(x^2+2x)=1
[7x+4]/(x^2+2x)=1
7x+4=x^2+2x
x^2-2x-7x-4=0
x^2-9x-4=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(9+-sqrt[-9^2-4*1*-4])/2*1
x=(9+-sqrt[81+16])/2
x=(9+-sqrt97)/2
x=(9+-9.85)/2
x=(9+9.85)/2
x=18.85/2
x=9.424 ans
x=(9-9.85)/2
x=-.85/2
x=-.424 ans.