Question 243262
A line perpendicular to 3x-7y+2=0 and passing through the point (3,7)
-7y=-3x-2
y=-3x/-7-2/-7
y=3x/7+2/7 this line has a slope=3/7.
A perpendicular line will have a slope=-7/3
Y=mX+b
7=-7/3*3+b
7=-21/3+b
7=-7+b
b=7+7
b=14 the Y intercept.
Y=-7x/3+14
{{{ graph( 300, 200, -6, 5, -10, 15, -7x/3 +14) }}} (graph 300x200 pixels, x from -6 to 5, y from -10 to 15, -7x/3 +14).