<PRE><B>Question 243203</B>
The setup of the problem tells us:
A + B + C = 180
A = 3B, so B = A/3 
A = C+16, C = A-16
Substitute into basic formula:
A + A/3 + A-16 = 180
2A + A/3 = 196
Getting rid of the fractional A is next:
{{{
2A = (6/3)A
}}}
...
So we have:
{{{
(6/3)A + A/3 = (6/3)A + (1/3)A = (7/3)A = 196
}}}
Which can be simplified by multiplying both sides by 3.
7A = 3*196 = 588
Dividing both sides by 7, we have:
A = 84
...
Looking back to the equations we define:
B = A/3 = 84/3 = 28
and 
C = A-16 = 68
...
To summarize:
A = 84
B = 28
C = 68
...
To check your work, check the solution to the fundamental equation.
Does A + B + C = 180?
84 + 28 + 68 = 180
So we have our answer.
...
Follow these same steps to answer your 2nd question.</PRE>