Question 31074
2x+3y=6............(1)

2x-y=-2............(2)

we solve the above equations by elimination method ... 
2x + 3y = 6
2x - y  = -2
-  +      +
--------------

    4y =  8

divide both sides by 4 ,,,and we get ...

y = 2

putting the values of y in any of the equation to get the value of x ,,,here i am taking equation (1)..we get 

2x+3y=6............(1)

2x + 3 * 2 = 6 

2x + 6 = 6 

subtract 6 from both sides and we get ...

2x  =  0 

divide both sides by 2 and we get ,,,,

x = 0

therefore the value are ....y = 2 and x = 0.....

Now if you want to verify you answer ,,,you can put the values of x and y in any of the equation and if you get LHS=RHS,,,this means that you answer is correct..