Question 243170
<pre><font size = 4 color = "indigo"><b>

{{{V = 4/3}}}{{{x}}}{{{pi}}}{{{x}}}{{{r^3}}} where {{{r}}} is the radius, which

is {{{1/2}}} the diameter.  Since the diameter is {{{100mm}}}, the

radius is {{{1/2}}} of {{{100mm}}} or {{{50mm}}}.  So we substitute

{{{50mm}}} for {{{r}}} in the equation:

{{{V = 4/3}}}{{{x}}}{{{pi}}}{{{r^3}}}

{{{V = 4/3}}}{{{x}}}{{{pi}}}{{{x}}}{{{(50mm)^3}}}

{{{V = 4/3}}}{{{x}}}{{{pi}}}{{{x}}}{{{50mm*50mm*50mm}}}

{{{V = 4/3}}}{{{x}}}{{{pi}}}{{{x}}}{{{125000mm^3}}}

For {{{pi}}} some people use {{{22/7}}} even though that 
is technically inaccurate but it is accurate to three 
significant figures. 
So we'll use it:

{{{V = 4/3}}}{{{x}}}{{{22/7}}}{{{x}}}{{{125000mm^3}}}

Using a calculator, that comes out

{{{523809.5238mm^3}}} 

but since it is accurate only to three significant
figures we round it to:

{{{524000mm^3}}} or if you prefer {{{524000cubic_millimeters}}}.

Did you want to convert that to cubic centimeters or milliliters?

If so post again.

Edwin</pre>