<PRE><B>Question 243101</B>
I am having a dinner party with five guests. I have 11 friends from which to choose as guests. 
From how many different collections of five dinner guests can i choose if two are married to each other and won&#39;t come seperatly?
---
Treat those two married persons as one person.
# of groups of 5 will be 10C5 = 1052
-------------------------------------------- 
From how many different collections of five dinner guests may she choose if two are divorced from each other and refuse to come together?
-------------------------
Choose one of those divorced folks: 2 ways
Choose 4 others to join that person: 9C4 = 126 ways
---------------------------
Total # of groups of 5: 2*126 = 252
=======================================
Cheers,
Stan H.
</PRE>