Question 243038
{{{2 ln(6) + 2 ln(z)}}} Start with the given expression.



{{{ln(6^2) + ln(z^2)}}} Use the identity  {{{y*ln(x)=ln(x^y)}}}



{{{ln(36) + ln(z^2)}}} Square 6 to get 36



{{{ln(36z^2)}}} Combine the logs using the identity {{{ln(A)+ln(B)=ln(A*B)}}}



So {{{2 ln(6) + 2 ln(z)=ln(36z^2)}}}