Question 242538
h= -0.002d^2 + 0.4d
where h is the height of the ball, in metres, and d is the horizontal distance the ball travels, in metres, until it first hits the ground.
a. What is the maximum height reached by the ball?
h(d) = -0.002d^2 + 0.4d
-0.002d^2 + 0.4d - h = 0
The vertex is at -b/2a = -0.4/-0.004 = 100
h(100) = -0.002*10000 + 40
max = 20 meters
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b, What is the horizontal distance of the ball from the golfer when the ball reaches its maximum height?
d at the vertex = 100 meters
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c. What distance does the ball travel horizontally until it first hits the ground?
The equation is symmetrical, so it's 2x the distance at the vertex
= 200 meters