Question 242941
{{{4/(x^2)+y^2}}} Start with the given expression.



{{{4/(x^2)+y^2((x^2)/(x^2))}}} Multiply the second term by {{{(x^2)/(x^2)}}}



{{{4/(x^2)+(x^2y^2)/(x^2)}}} Combine the fractions.



{{{(4+x^2y^2)/(x^2)}}} Add the fractions.



{{{(x^2)/(4+x^2y^2)}}} Flip the fraction.



So the reciprocal of {{{4/(x^2)+y^2}}} is {{{(x^2)/(4+x^2y^2)}}}