Question 242938


{{{(x-2)(x^2-4x+3)}}} Start with the given expression.



{{{x(x^2-4x+3)-2(x^2-4x+3)}}} Expand.



{{{(x)*(x^2)+(x)*(-4x)+(x)*(3)+(-2)*(x^2)+(-2)*(-4x)+(-2)*(3)}}} Distribute.



{{{x^3-4*x^2+3*x-2*x^2+8*x-6}}} Multiply.



{{{x^3-6*x^2+11*x-6}}} Now combine like terms.



 So {{{(x-2)(x^2-4x+3)}}} expands to {{{x^3-6*x^2+11*x-6}}}.



In other words, {{{(x-2)(x^2-4x+3)=x^3-6*x^2+11*x-6}}}.