Question 242918
You are correct. Recall that {{{log(b,(x))=log(10,(x))/log(10,(b))}}}.


So in this case, {{{log(a,(a^8))=log(10,(a^8))/log(10,(a))=(8*log(10,(a)))/log(10,(a))=(8*cross(log(10,(a))))/cross(log(10,(a)))=8}}}.



In other words, {{{log(a,(a^8))=8}}}