<PRE><B>Question 242782</B>
how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0
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cube root of (4+6t) - 3[the cube root of (1-8t)] = 0
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cbrt(4+6t) = 3*cbrt(1-8t)
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Raise both sides to the 3rd power
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4+6t = 27(1-9t)
4+6t = 27 - 243t
249t = 23
t = 23/249
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Cheers,
Stan H. </PRE>