Question 242771
Can be rewritten as {{{(3x-6)/3 - (1/(5x+10)) = 12}}}

{{{(x-2) - (1/(5x+10)) = 12}}}

{{{ - (1/(5x+10)) = 12-(x-2)}}}

{{{ (1/(5x+10)) = (x-2)-12}}}

{{{ (1/(5x+10)) = (x-14)}}}

{{{ 1 = (5x+10)(x-14)}}}

{{{ 1 = (5x^2-70x+10x-140)}}}

{{{ 0 = (5x^2-60x-141)}}}

{{{ 0 = x^2-12x-(141/5)}}}

{{{ 0 = (x-6)^2-36-(141/5)}}}

{{{ 321/5 = (x-6)^2}}}

{{{ sqrt(321/5)+6 = x}}}

x = -2.01 OR x=14.01