Question 242724
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Let *[tex \Large x] represent the numerator.  Then the denominator must be *[tex \Large 4x\ -\ 3].  Hence the fraction is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{4x\ -\ 3}]


If you add 5 to both terms (I presume that means add 5 to both numerator and denominator) you get:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ 5}{4x\ +\ 2}]


And this is equal to one-half, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ 5}{4x\ +\ 2}\ =\ \frac{1}{2}]


Now all you have to do is cross-multiply and solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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