Question 242750
x+y+z=-6
x-y+4z=6
5x+y+z=-26
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Subtract 1st from 2nd;
Subtract 5*1st from 3rd:
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x+y+z=-6
0x-2y+3z=12
0x-4y-4z=4
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Simplify 3rd:
x+y+z=-6
0x-2y+3z=12
0x-2y-2z=2
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Subtract 2nd from 3rd:
x+y+z=-6
0x-2y+3z=12
0x+0y-5z=-10
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Solve 3rd to get z = 2
Substitute into 2nd to solve for "y": y = -3
Substitute into 1st to solve for "x": x = -5
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Cheers,
Stan H.