Question 242746
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<img src="http://www.math.ucsd.edu/~jarmel/math4c/Unit_Circle_Angles.png">


On the unit circle, the *[tex \LARGE x]-coordinate is the *[tex \LARGE \cos] and the *[tex \LARGE y]-coordinate is the *[tex \LARGE \sin]


Hence, *[tex \LARGE \sin\left(\frac{\pi}{6}\right)\ =\ \frac{1}{2}] and *[tex \LARGE \cos\left(\frac{\pi}{3}\right)\ =\ \frac{1}{2}].


Since


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin^2(x)\ =\ \left(sin(x)\right)^2]


you can just substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{1}{2}\right)^2\ +\ \left(\frac{1}{2}\right)^2]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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