Question 242731
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ =\ 3x]


Add *[tex \Large -3x] to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ -\ 3x\ =\ 0]


Now you can factor out an *[tex \Large x] leaving you with two linear factors, either one of which must be equal to zero.


The lesson here is that the first step in the solution of any polynomial equation is to put everything in the LHS and make the RHS be zero.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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