Question 242564
Problem:  {{{2sqrt(50)+8sqrt(2)}}}
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Let's make the first term have the same square root as the second so we can then add the terms.  Here's how to do it:
Let's take a look at the square root of 50 and square root of 2.  Can we divide 50 by 2?  Yes, it's 25.  
Therefore, we can say {{{sqrt(50)}}} = {{{sqrt(25*2)}}}
We can further say that {{{sqrt(25*2)}}} = {{{sqrt(25)*sqrt(2)}}}.
Therefore, we can change the original expression to:
{{{2(sqrt(25)*sqrt(2))+8sqrt(2)}}}
Now, does 25 have a square root? Yes, it's 5.  So we get:
{{{(2*5)sqrt(2)+8sqrt(2)}}}
{{{10sqrt(2)+8sqrt(2)}}}
{{{18sqrt(2)}}} <--- this is our final expression.