Question 242314
Let {{{u^2=x}}}, {{{u=x^(1/2)}}}, then
{{{2x+x^(1/2)-3=0}}}
{{{2u^2+u-3=0}}}
Factor
{{{(2u+3)(u-1)=0}}}
Two solutions
{{{2u+3=0}}}
{{{u=-3/2}}}
{{{x=u^2=9/4}}}
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{{{u-1=0}}}
{{{u=1}}}
{{{x=u^2=1 }}}