Question 242356
Use these exponentiation rules
{{{(x^M)*(x^N)=x^(M+N) }}}
{{{(x^(M))^N=x^(M*N)}}}
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{{{ (270*t^8)^(1/3)=(27*10*t^6*t^2)^(1/3)}}}
{{{(270*t^8)^(1/3)=(27)^(1/3)*(t^6)^(1/3)*(10t^2)^(1/3)}}}
{{{27=3^3}}}
{{{27^(1/3)=(3^3)^(1/3)=3}}}
{{{(t^6)^(1/3)=t^2}}}
{{{(270*t^8)^(1/3)=3t^2*(10t^2)^(1/3)}}}