Question 242206
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I think you mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{-x\ +\ 5}{6}\ =\ \frac{1}{2}]


Multiply both sides of the equation by 6:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -x\ +\ 5\ =\ 3]


Add -5 to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -x\ =\ -2]


Multiply both sides of the equation by -1:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 2]


Check the answer:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{-(2)\ +\ 5}{6}\ =^?\ \frac{1}{2}] 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{6}\ =^?\ \frac{1}{2}]


Yep, checks.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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