Question 242158
In order to determine the value of x, we need to take the square root of both sides of the equation.  In this case, we will not get a nice integer, instead we will get a decimal result.  But that's ok... it doesn't mean that is wrong, it is just uncommon.  Most problems are setup in such a way to yield whole numbers (integers).
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Problem:
{{{x^2=180}}}
{{{sqrt(x^2)=sqrt(180)}}}
Note: when we take the square root of a squared exponent, they cancel each other out.  So, we are left with:
{{{x=sqrt(180)}}}
Now, you may leave it like this {{{sqrt(180)}}} or calculate the decimal equivalent using your calculator.  Which would be: {{{x=13.42}}} <-- result has been rounded.