Question 31004
The equation would be {{{(3+2x)/(x+1)=3/2}}}

from here is is just solving for x
{{{(3+2x)/(x+1)=3/2}}} multiply both sides by (x+1)
{{{3+2x=3/2*(x+1)}}} distribute the 3/2
{{{3+2x=3/2x+3/2}}} combine like terms (constants first)
{{{3/2+2x=3/2x}}} combine like terms (now variables)
{{{3/2=-1/2x}}} multiply both sides by -2 
{{{-3=x}}}

check your answer:
{{{(3+2x)/(x+1)=3/2}}}
{{{(3+2(-3))/((-3)+1)=3/2}}}
{{{(3-6)/(-3+1)=3/2}}}
{{{(-3)/(-2)=3/2}}}
{{{3/2=3/2}}}