Question 31003
Hello!
We have:
{{{3log4(a-2)=(9/2)}}}

First let's divide by 3:

{{{log4(a-2) = 9/(2*3) = 9/6 = 3/2}}}

The we use the following identity.
If {{{logz(x) = y}}} then {{{x = z^y}}}

So, since we have {{{log4(a-2) = 3/2}}}, this implies that

{{{a-2 = 4^(3/2)}}}
{{{a = 4^(3/2) + 2}}}


I hope this helps!
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