Question 241964
2x^2+3x-1
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(-3+-sqrt[3^2-4*2*-1])/2*2
x=(-3+-sqrt[9+8])/4
x=(-3+-sqrt17)/4
x=(-3+-4.123)/4
x=(-3+4.123)/4
x=1.123/4
x=.28 ans.
x=(-3-4.123)/4
x=-7.123/4
x=-1.78 ans.