Question 240925
Let x = integer
Let x+2 = consecutive even integer
Now, the sum of the larger and three times the smaller is 234. So the equation then becomes:
{{{(x+2)+3x=234}}}
{{{4x+2=234}}}
{{{4x=234-2}}}
{{{x=232/4}}}
{{{x=58}}} <--- this is your smaller integer
.
{{{x+2=58+2=60}}} <--- this is the consecutive even integer.
.
Check: Remember the original equation 
{{{(x+2)+3x=234}}}
{{{(58+2)+3*58=234}}}
{{{60+174=234}}}
{{{234=234}}}
.
Done!  :)