Question 241607
{{{m = 2a}}}
{{{m^2 + a^2 = 80}}}
By substitution,
{{{(2a)^2 + a^2 = 80}}}
{{{4a^2 + a^2 = 80}}}
{{{5a^2 = 80}}}
{{{a^2 = 16}}}
{{{a = 4}}}
and, since
{{{m = 2a}}}
{{{m = 2*4}}}
{{{m = 8}}}
Molly is 8 and Anita is 4