Question 241561
RM = Malaysian Ringgit


x = number of footballs that can be bought for 120 rm.


120/x = price of one football.


reduce price of one football by 6 rm.


price of one football becomes (120/x) - 6


now you can buy one extra football for the same price as before (120 rm).


x * (120/x) = 120


(x+1) * ((120/x)-6) = 120


since they both equal to 120 then they are equal to each other.


x * (120/x) = (x+1) * ((120/x)-6)


multiply both sides by x to get:


x * 120 = (x + 1) * ((120 - 6x))


simplify by removing parentheses to get:


120*x = 120*x - 6x^2 + 120 - 6x


subtract 120*x from both sides to get:


120*x - 120*x - 6x^2 + 120 - 6x = 0


combine like terms to get:


-6x^2 + 120 - 6x = 0


multiply both sides by -1 to get:


6x^2 - 120 + 6x = 0


reorder terms on left side of equation to get:


6x^2 + 6x - 120 = 0


divide both sides by 6 to get:


x^2 + x - 20 = 0


factor to get:


(x+5) * (x-4) = 0


solve for x to get:


x = -5 or x = 4


x can't be negative so x = 4


Efendi buys 4 footballs for 120 rm.


he pays 30 rm apiece because 4 * 30 = 120.


price is reduced by 6 rm apiece.


price becomes 24 rm apiece.


he can now buy 5 footballs at 24 rm apiece because 5 * 24 = 120.