Question 241467
I think it looks like this:

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 )___ )
  
The area of the semi-circle added to one side
is {{{(1/2)*pi*x^2}}}
The area of the square is {{{2x*2x = 4x^2}}}
So far the area of the sign is
{{{4x^2 + (1/2)*pi*x^2}}}
The semi-circle that is removed 
has radius = {{{x/2}}}
It's area is {{{(1/2)*pi*(x/2)^2}}}
So, the area of the sign is
{{{4x^2 + (1/2)*pi*x^2 - (1/2)*pi*(x/2)^2}}}
{{{4x^2 + (1/2)*pi*x^2 - (1/2)*pi*(x^2/4)}}}
Factor out {{{x^2}}}
{{{x^2*(4 + (1/2)*pi - (1/8)*pi)}}}
Factor out {{{pi}}}
{{{x^2*(4 + (1/2 - 1/8)*pi)}}}
{{{x^2*(4 + (3/8)*pi)}}}
Hope I got it