Question 241437
Let {{{n}}} = the number of years from now when
Rose will be twice as old as Peggy
{{{4 + n}}} will be Peggy's age then
{{{10 + n}}} will be Rose's age then
given:
{{{10 + n = 2*(4 + n)}}}
{{{10 + n = 8 + 2n}}}
Subtract {{{8}}} from both sides
{{{2 + n = 2n}}}
{{{n = 2}}}
In 2 years, Rose will be twice as old as Peggy
check:
{{{10 + n = 2*(4 + n)}}}
{{{10 + 2 = 2*(4 + 2)}}}
{{{12 = 2*6}}}
{{{12 = 12}}}
OK