Question 241381
(4x/x-2) = x+ (8/x-2) 
This is what I did to get my answer: 
(4x/x-2) = x+ (8/x-2) 
4x = x(x-2) + 8
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4x = x^2 - 2x + 8
x^2 - 6x + 8 = 0
(x-4)*(x-2) = 0
x = 4
x = 2 (2 causes the dreaded "Divide by 0" error, so reject it)
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I don't see how you did, but you got to the same place.
4x =  - 2x + 8 
-4x -4x 
 - 6x + 8 
(x-4)(x-2)