Question 241366
find the vertex, the line of symmetry,
the maximum or minimum value of the quadratic 
function and graph the function
f(x)=7-x2 and find zeros
You have a quadratic with a = -1, b = 0, c = 7
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Max or min occurs when x = -b/2a = -0/-2 = 0
f(0) = 7
So the vertex is (0,7)
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Axis of symmetry is x=0
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Zeroes: 7-x^2 = 0
x^2 = 7
x = +sqrt(7) ; x = -sqrt(7)
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Graph:
{{{graph(400,300,-10,10,-10,10,7-x^2)}}}
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Cheers,
Stan H.