Question 241259
how long will it take for $1000 to grow to $42,900 at an interest rate of 10.6% if the intrest is compounded continuously? Round the number of years to the nearest hundredth. 
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A(t)=Pe^(rt)
42,900 = 1000*e^(0.106t)
Divide by 1000 to get:
e^0.106t = 42.9
Take the natural log to get:
0.106t = 3.75887..
t = 35.46 years
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Cheers,
Stan H.