Question 241220
Perform the indicated operations and simplify.
[x^2/3x^2-5x-2]-[2x/3x+1]∙[1/(x-2)]
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Factor where you can:
[x^2/(x-2)(3x+1]-[2x/3x+1]∙[1/(x-2)]
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lcd = (x-2)(3x+1)
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Write each fraction with the lcd as its denominator:
[x^2/lcd] - [2x/lcd]
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Combine the numerators over the lcd:
(x^2-2x]/[(x-2)(3x+1)]
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(x(x-2))/[(x-2)(3x+1)]
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x/(3x+1)
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Cheers,
Stan H.