Question 241069
how to solve this equation using direct variation? 5x-6y=0
<pre>
y varies directly with x.  So we write

y = kx


We can see that when x=6 and y=5, the equation
5x-6y=0 is true, for 5(6)-6(5)=0

So we substitute these values in

y = kx

5 = k(6)

Divide both sides by 6

{{{5/6=k}}}

Therefore replacing k by {{{5/6}}} in y=kx we have

y = {{{5/6}}}x

Edwin</pre>