<PRE><B>Question 240895</B>
 the number of bacteria present in a culture after t minutes is given as B=100e^kt. 
If there are 3367 bacteria present after 8 minutes, find k.
:
Replace t with 8 and B with 3367
:
100e^(8k) = 3367
:
Divide both sides by 100
e^(8k) = {{{3367/100}}}
:
e^(8k) = 33.67
:
Find the nat log of both side, 
ln(e^8k) = ln(33.67)
:
8k*ln(e) = ln(33.67
:
nat log of e is 1 
8k = 3.5166
:
k = {{{3.5166/8}}}
k = .4396
:
:
Check solution on a good calc: enter 100*e^(8*.4396) ~ 3367
</PRE>