Question 240848
 2/A = 3A/(5A-14) CROSS MULTIPLY.
3A^2=2(5A-14)
3A^2=10A-28
3A^2-10A+28=0
{{{A = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
A=(10+-SQRT[-10^2-4*3*28])/2*3
A=(10+-SQRT100-336)/6
A=(10+-SQRT-236)/6
A=(10+-15.36i)/6
A=(10/6+-15.36i/6
A=1.667+-2.56i ans.