Question 240804
For sin and cos, if you write the equation in the form:
{{{f(x) = C + A*sin(B(x-D))}}}
or
{{{f(x) = C + A*cos(B(x-D))}}}
The numbers you find for A, B, C and D will tell you a lot about the function:
A = the amplitude.
B = {{{2pi}}}/period or 360/period depending on if you are using radians or degrees
C = the vertical shift
D = the horizontal (or phase shift)<br>
Your equation is almost in the right form. We just need to factor the 2 in the argument:
{{{F(x)=3 sin (2x-4) = 3sin(2(x-2))}}}
Now we can "read" the equation:
A = 3 so the amplitude is 3.
B = 2 so we could use {{{2 = 2pi}}}/period to find the period if we wanted it.
C is missing so it is zero. There is no vertical shift.
D = 2 so the horizontal or phase shift is 2 (to the right). (A negative D would be a shift to the left.)