<PRE><B>Question 240792</B>
In the following exercise, find the coordinates of the vertex for the parabola defined by the given quadratic function.
f(x)=4x^2+8x+1 
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The vertex occurs where x = -b/2a = -8/(2*4) = -1
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f(-1) = 4(-1)^2 + 8(-1) + 1
f(-1) = 4-8+1
f(-1) = -3
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Vertex: (-1,-3)
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Cheers,
Stan H.</PRE>