Question 240763
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Use:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(n\cr k\right)\ =\ \frac{n!}{k!(n-k)!}]


to determine the number of *[tex \Large n] things taken *[tex \Large k] at a time.


For your first question, you need 59 things taken 5 at a time:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(59\cr\ 5\right)\ =\ \frac{59!}{5!(59-5)!}]


For your second question, you need 39 things taken 1 at a time:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(39\cr\ 1\right)]


Hint:  for any *[tex \Large n], 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(n\cr 1\right)\ =\ \left(\ \,n\cr n-1\right)\ =\ n]


The answer to the third question is the sum of the first two answers.


You get to do your own arithmetic.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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