Question 240559
{{{2*log(4,x)+log(4,3)=log(4,x)-log(4,2)}}}


{{{log(4,x^2)+log(4,3)=log(4,x)-log(4,2)}}}
{{{log(4,3x^2)=log(4,x/2)}}}
{{{3x^2=x/2}}}


Multiply both sides by 2:
{{{6x^2 =x}}}
{{{6x^2-x=0}}}


Factor the x:
{{{x(6x-1)=0}}}
There are two solutions:
x=0 NOTE:  THIS ANSWER MUST BE REJECTED, SINCE log(0) is UNDEFINED!!


6x-1=0
6x=1
x=1/6  This one seems to work!!


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus