Question 240634
Are you allowed to use a graphing calculator or graphing techniques???


If so, then sketch y=(x+2)(x-11)(x+1).


This graph has zeros at x=-2, x=11, and x=-1.  Sketch the graph using x values (based upon the zeros that you just found!) from x=-5 to x = 15.  Values of y must be larger, but you can try using values from -100 to 100.  I'll use the algebra.com calculator and see what it looks like:

{{{graph(300,300,-5,15,-100,100, (x+2)(x-11)(x+1))}}}


Now, since you are solving the inequality (x+2)(x-11)(x+1)>0, you need to find all values of x for which the graph y=(x+2)(x-11)(x+1) are ABOVE the x axis.


This would be values of x from -2 to -1 or values of x from 11 to infinity.

{x|-2 < x <-1} U  {x|x > 11} 


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida