Question 240471
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Let *[tex \Large w] represent the width.  Then *[tex \Large w\ + 20] represents the length.  Since the area of a rectangle is the length times the width:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ 20w\ =\ 2925]


Put the quadratic in standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ 20w\ -\ 2925\ =\ 0] 


Now all you need to do is solve the quadratic and take the positive root as the width and add 20 to get the length.  Hint: It factors.


-45 times 65 = -2925



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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