Question 240452
The problem is: 
[(x-1)/(x^2+1)] times [(x^4-1)/(x-1)^2] times [(x^2-1)/(x^4-2x^2+1)]
------------------------------------------------------------------
Factor where you can; cancel any factor common to a numerator and a denom.
----------------------------- 
[1/1] times [1/(x-1)] 
times [1/1]
-----------------------------------------------------
= 1/(x-1)
=================
Cheers,
Stan H.