Question 240294
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{1}{2}h(b_1\ +\ b_2)]


Multiply by 2:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2A\ =\ h(b_1\ +\ b_2)]


Multiply by *[tex \LARGE \frac{1}{h}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2A}{h}\ =\ b_1\ +\ b_2]


Add *[tex \LARGE -b_2] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b_1\ =\ \frac{2A}{h}\ -\ b_2]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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