Question 240211
{{{2x^2 > 5x+3}}}
:
{{{2x^2-5x-3>0}}}
Factor this and we have
(x-3)(2x+1) = 0
but the inequality will be
x > 3
and
2x < 1
x < {{{1/2}}}
:
More apparent if you graph it
{{{ graph( 300, 200, -6, 5, -10, 10, 2x^2-5x-3) }}}
note that it is greater than 0 below -.5 and above +3
:
You can see if you substitute x=+1, or x=+2, the inequality will not be true