Question 240143
Do the following. (Round the answers to six decimal places.) 
(a)Find the probability of being dealt an "aces over kings" full house (three aces and two kings).
# of ways to pick three aces: 4C3 = 4
# of ways to pick 2 kings: 4C2 = 6
-------------------------------------------
Prob = (4*6)/52C5 = 0.000009234

=============================================
Probability of being dealt a full house.
Pick a card: 13 ways
Pick 3 of the card: 4 ways
Pick another card: 12 ways
Pick 2 of that card: 6
----------------------------------
Prob = {13*4*12*6)/52C5 = 3744/2598960 = 0.00144....
------------------------------------------------------
Cheers,
Stan H.