Question 240126
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You can't prove that NI bisects angle INE.  That's because NI doesn't bisect INE.


Now, if you were just being careless and actually meant to say "prove that NL bisects angle INE", then proceed thus:  (Note: This system won't render the congruence symbol, so I have substituted the identity symbol (&#8801;)


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ IN\ ]&#8801;*[tex \LARGE \ NE\ \ \ \ ] Given.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ IL\ \ ]&#8801;*[tex \LARGE \ LE\ \ \ \ ] Definition of midpoint


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ NL\ ]&#8801;*[tex \LARGE \ NL\ \ \ \ ] Reflexive Property of Equality


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \Delta INL\ ]&#8801;*[tex \LARGE \ \Delta ENL\ \ \ \ ] SSS


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \angle INL\ ]&#8801;*[tex \LARGE \ \angle ENL\ \ \ \ ] CPCTC


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ NL\ ] bisects *[tex \LARGE \ \angle INE\ \ \ \ ] Definition of Angle Bisector



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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