Question 240036
First prepare a mini formula for the integers.
x = integer
x+2 = consecutive even integer
x+4 = next consecutive even integer
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Now workout the problem:
If the middle of three consecutive even integers is added to 100 (x+2+100) 
the result is (=)
42 more than the sum (42+)
of the largest (x+4)
and twice the smallest (2x)
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Your formula then becomes:
{{{(x+2)+100=42+(x+4)+2x}}}
Now workout the algebra to solve for x.  This wil give you the smallest integer.
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Remember to check your answers by pluggin in the results in the original formula.  Both sides of the equation must equal, otherwise you've done something wrong along the way.  :)