Question 239579
The Point-Slope Form of a Line is {{{y-y1=m(x-x1)}}}
All we will need to do here is to substitute the given values and present the equation. So:
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Point (-2,-1) and m=3
{{{y-(-1)=3(x-(-2))}}}
{{{y+1=3(x+2)}}}
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Point (6,-1) and m=0
{{{y-(-1)=0(x-(-2))}}}
{{{y+1=0(x+2)}}}
Now, any number multiplied by zero equals zero... so verify with your professor whether or not he/she wants you to simplify this to: {{{y+1=0}}}